(type 2) Calculate mEq per volume from mg or percent

5. mEq and mOsmol 5.1) mEq 5.1.1) mEq - General

5.1.1.1) mEq from weight/volume Normal 1


Total tried:       Correct:       Wrong:

A solution contains 300 mg of sodium bicarbonate in each 100 mL (the MW of sodium bicarbonate is 84). Express it as mEq/mL.


Click on the button below to see the answer and explanations


Notice: Undefined variable: input_value1 in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 220
lb equals 0.0357 mEq/mL kg

    The molecular weight of sodium bicarbonate = 84.
    Valence or charge = 1.
    Therefore, we can write: 84 mg = 1 mEq.
    Since the question needs mEq/mL as the final unit, we keep mEq in the starting numerator. So, 84 mg will be the denominator.
    Also, the solution contains 300 mg per 100 mL. In order to cancel out mg, we need to keep 300 mg in the numerator of the second fraction. Therefore, the dimensional analysis will be like this:

    `(1 \quad mEq)/(84 \quad mg) × (300 \quad mg)/(100 \quad mL) =0.0357\quad (mEq)/(mL)` Ans.


Notice: Undefined index: TOTALTRY in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 675