(type 2) Calculate mEq per volume from mg or percent

5. mEq and mOsmol 5.1) mEq 5.1.1) mEq - General

5.1.1.1) mEq from weight/volume Normal 1


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A solution contains 10 mg of NaCl in each 10 mL (the MW of NaCl is 58.5). How many milliequivalent of NaCl will be present per liter of this solution?


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lb equals 17.09 mEq/L kg

    The molecular weight of NaCl = 58.5.
    Valence or charge = 1.
    Therefore, we can write: 58.5 mg = 1 mEq.
    Since the question needs mEq/L as the final unit, we keep mEq in the numerator. So, 58.5 mg will be the denominator.
    Also, the solution contains 10 mg per 10 mL. To cancel out mg, we need to keep 10 mg in the numerator of second fraction. Therefore, the dimensional analysis will be like this:

    `(1 \quad mEq)/(58.5 \quad mg) × (10 \quad mg)/(10 \quad mL) × (1000 \quad mL)/(1 \quad L)=17.09\quad (mEq)/L` Ans.