Regimen: Stanford V for Hodgkin lymphoma PO dose

6. Patient-based Dose 6.5) Chemo Dose Clculation 6.5.5) PO dose of Stanford V

6.5.4.1) PO dose per cycle of Stanford V Normal 1


Total tried:       Correct:       Wrong:

Regimen : Stanford V for Hodgkin lymphoma.
Cycle: three 4-week cycles. Total regimen is 12 weeks.

  • Doxorubicin, 25 mg/m2, IV, weeks 1, 3, 5, 7, 9 and 11
  • Mechlorethamine, 6 mg/m2, IV, weeks 1, 5 and 9
  • Vinblastine, 6 mg/m2, IV, weeks 1, 3, 5, 7, 9 and 11
  • Vincristine, 1.54 mg/m2, IV, weeks 2, 4, 6, 8, 10 and 12.
  • Bleomycin, 5 units/m2 , IV, weeks 2, 4, 6, 8, 10 and 12.
  • Etoposide, 60 mg/m2 per day IV on 2 consecutive days in weeks 3, 7, 11
  • Prednisone, 40 mg/m2 PO every other day for 10 weeks then tapered by 10 mg PO every other day between week 10 and 12
For prednisone calculate the total PO dose in 12 weeks for a patient measuring 5 feet in height and weighing 130 lb.


Click on the button below to see the answer and explanations

lb equals 2366.00 mg kg

  • The patient height
    = 5 feet
    = ( 5 × 12 ) inch
    = 60 inch
    = 60 × 2.54 cm
    = 152.4 cm

  • patient weight
    = 130 lb
    = 130 × 0.454 kg
    = 59.0 kg

  • BSA for the patient is

    BSA `= \quad sqrt(( Height (cm) × Weight (Kg) )/(3600))`

    ` \quad \quad \quad = sqrt(( 152.4 \quad cm × 59.0 \quad Kg )/(3600)) = 1.5804 ` m2

  • Here for prednisone :

    patient dose for every other day
    = `( 40 \quad mg)/(1quad m^2) × 1.5804 m^2
    = 63 ` mg

    Hence, dose for first 10 weeks
    = ` 63 \quad mg × 35` (days of treatment)
    = 2205 mg

    And dose for `11^(th)` and `12^(th)` weeks (7 days of treatment tapered by 10 mg)
    = ( 53 + 43 + 33 + 23 + 13 + 3 + -7 ) mg
    = 161 mg

    Therefore, total dose for 12 weeks cycle
    = 2205 mg + 161 mg = 2366 mg `Ans.`