Regimen: Stanford V for Hodgkin lymphoma PO dose
6. Patient-based Dose 6.5) Chemo Dose Clculation 6.5.5) PO dose of Stanford V
6.5.4.1) PO dose per cycle of Stanford V Normal 1
Total tried: Correct: Wrong:
Regimen : Stanford V for Hodgkin lymphoma.
Cycle: three 4-week cycles. Total regimen is 12 weeks.
- Doxorubicin, 25 mg/m2, IV, weeks 1, 3, 5, 7, 9 and 11
- Mechlorethamine, 6 mg/m2, IV, weeks 1, 5 and 9
- Vinblastine, 6 mg/m2, IV, weeks 1, 3, 5, 7, 9 and 11
- Vincristine, 1.61 mg/m2, IV, weeks 2, 4, 6, 8, 10 and 12.
- Bleomycin, 5 units/m2 , IV, weeks 2, 4, 6, 8, 10 and 12.
- Etoposide, 60 mg/m2 per day IV on 2 consecutive days in weeks 3, 7, 11
- Prednisone, 40 mg/m2 PO every other day for 10 weeks then tapered by 10 mg PO every other day between week 10 and 12
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lb equals 4802.00 mg kg
- The patient height
= 6 feet 2 inches
= ( 6 × 12 + 2 ) inch
= 74 inch
= 74 × 2.54 cm
= 187.96 cm - patient weight
= 389 lb
= 389 × 0.454 kg
= 176.6 kg -
BSA for the patient is
BSA `= \quad sqrt(( Height (cm) × Weight (Kg) )/(3600))`
` \quad \quad \quad = sqrt(( 187.96 \quad cm × 176.6 \quad Kg )/(3600)) = 3.0365 ` m2
-
Here for prednisone :
patient dose for every other day
= `( 40 \quad mg)/(1quad m^2) × 3.0365 m^2
= 121 ` mg
Hence, dose for first 10 weeks
= ` 121 \quad mg × 35` (days of treatment)
= 4235 mg
And dose for `11^(th)` and `12^(th)` weeks (7 days of treatment tapered by 10 mg)
= ( 111 + 101 + 91 + 81 + 71 + 61 + 51 ) mg
= 567 mg
Therefore, total dose for 12 weeks cycle
= 4235 mg + 567 mg = 4802 mg `Ans.`