Dilution Problem - Find Initial Concentration

9. Altering Product Strength 9.1) Dilution 9.1.1) Dilution

9.1.1.1) Find initial concentration in dilution Easy 1


Total tried:       Correct:       Wrong:

What concentration of a 49.5 mL solution do you need to make 312.5 mL of a 5.74% solution?


Click on the button below to see the answer and explanations


Notice: Undefined variable: input_value1 in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 220
lb equals 36.25 % kg

    This is a volume expansion or concentration dilution type problem. The essential formula is `Q_1C_1 = Q_2C_2`.
    Here,

    `Q_1` = initial quantity = `49.5\quadmL`.
    `C_1` = initial concentration = `?\quad%`
    `Q_2` = final quantity = `312.5\quad mL`.
    `C_2` = final concentration = `5.74\quad %`

    Therefore, rearranging the formula, we get:
    `C_1 = (Q_2 × C_2)/(Q_1)`

    `therefore C_1 = (312.5 × 5.74) /49.5=36.25\quad%` (Ans.).


Notice: Undefined index: TOTALTRY in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 675