Type 1 - Alligation basic tic-tac-toe

9. Altering Product Strength 9.2) Alligation 9.2.1) Alligation

9.2.1.1) Alligation Normal 1


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How many grams of 6 % of a powder do you need to mix with 49 % of a powder in order to obtain 11 g of 12 % of a mixture?


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lb equals 9.47 g kg

    Tic-tac-toe, Short form:

    `[[49 %,\quad\quad\quad\quad, 6 pt],[\quad\quad\quad\quad,12 % (11\quad g), \quad\quad\quad\quad],[6 %,\quad\quad\quad\quad,37 pt]]`

    Tic-tac-toe, Long form:

    `[[49 %,\quad\quad\quad\quad, 6 pt, => 11 g × (6 pt)/(6 pt+37 pt)=, 1.53 g],[\quad\quad\quad\quad,12 % (11\quad g), \quad\quad\quad\quad, \quad\quad\quad\quad, \quad\quad\quad\quad],[6 %,\quad\quad\quad\quad,37 pt,=> 11 g × (37 pt )/(6 pt+37 pt)= ,9.47 g]]`

    Therefore, 9.47 g of 6 % will be required.


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