T20: C0 from AUC and K
50. Pharmacokinetics 50.1) PK Basic parameters 50.1.3) Area Under Curve (AUC)
50.1.3.1) AUC basic concepts Normal 1
Total tried: Correct: Wrong:
75.64 mg of a drug (elimination rate constant 0.071 h-1) was administered to a patient as an IV push. The plasma concentration over the time (AUC) was found to be 19.44 mg × h/L. Calculate the initial plasma concentration after administration of the drug.
Click on the button below to see the answer and explanations
lb equals 1.38 mg/L kg
-
We know that, AUC may be calculated from dose (`X_{0}`) and clearance (`Cl`) OR initial concentration (`C_{0}`) and the elimination rate constant (`K`).
` AUC = (X_{0})/(Cl) = (C_{0})/K`.
By rearranging the equation, we find:
`C_{0}=AUC × K`
`C_{0}=(19.44 \quad mg × h)/L × 0.071 \quad h^{-1} = 1.38 \quad (mg)/L`. Ans.