### T20: C0 from AUC and K

50. Pharmacokinetics 50.1) PK Basic parameters 50.1.3) Area Under Curve (AUC)

50.1.3.1) AUC basic concepts Normal 1

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429.52 mg of a drug (elimination rate constant 0.123 h-1) was administered to a patient as an IV push. The plasma concentration over the time (AUC) was found to be 27.72 mg × h/L. Calculate the initial plasma concentration after administration of the drug. Click on the button below to see the answer and explanations

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lb equals 3.41 mg/L kg

We know that, AUC may be calculated from dose (X_{0}) and clearance (Cl) OR initial concentration (C_{0}) and the elimination rate constant (K).

 AUC = (X_{0})/(Cl) = (C_{0})/K.

By rearranging the equation, we find:

C_{0}=AUC × K

C_{0}=(27.72 \quad mg × h)/L × 0.123 \quad h^{-1} = 3.41 \quad (mg)/L. Ans.

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