T05: (1→5) Mixed types of problems
50. Pharmacokinetics 50.1) PK Basic parameters 50.1.2) Clearance
50.1.2.1) Clearance basic concepts Normal 1
Total tried: Correct: Wrong:
If a patient weighing 192 Kg is given 112.896 mg of drug as an IV bolus, then determine the concentration of the drug in the blood. For this drug, the volume of distribution is 0.2 L/Kg.
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lb equals 2.94 mg kg
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Total volume of distribution (V) for this patient will be:
`0.2 \quad L/(Kg) × 192 \quad Kg = 38.4 \quad L`
Drug quantity (`X_{0}`) =112.896 mg
Concentration (`C_{0}`) = ?
We know that,
`C_{0}=X_{0}/V`
`therefore C_{0} = (112.896 \quad mg)/ (38.4 \quad L) = 2.94 \quad (mg)/L`. Ans.