T20: Mixed types from T12-T20
50. Pharmacokinetics 50.1) PK Basic parameters 50.1.3) Area Under Curve (AUC)
50.1.3.1) AUC basic concepts Normal 1
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Determine the elimination rate constant of a drug from the provided information. The volume of distribution is 18.27 L after administering 79.66 mg of the drug. The area under the plasma drug concentration over time (AUC) was found to be 13.42 mg × h/L.
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lb equals 0.33 h-1 kg
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We know that, `AUC=(dose)/(K × V)`.
`⇒ K=(dose)/(V × AUC)`
Plugging the values in this equation we get:
` K = (79.66 \quad mg)/(18.27 \quad L × 13.42 (mg × h)/L)`
` ∴ K=0.325 \quad h^{-1}`. Ans.