T20: Mixed types from T01-T20
50. Pharmacokinetics 50.1) PK Basic parameters 50.1.3) Area Under Curve (AUC)
50.1.3.1) AUC basic concepts Normal 1
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The plasma half life `t_{1/2}` of a drug is 4.1 h. If its volume of distribution in a patient is 96.94 L, then determine the clearance of the drug.
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lb equals 16.383 L/h kg
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We know that, clearance (Cl) is the product of elimination rate constant (K) and volume of distribution (V).
` Cl = K × V `.
Also, the relationship between K and plasma half life, `t_{½}` is:
`t_{½}=0.693/K ⇒ K=0.693/(4.1 \quad h)=0.169 \quad h^{-1}`
Plugging the values given in this question we get:
` Cl = 0.169 \quad h^{-1} × 96.94 \quad L = 16.38 \quad L/h ` Ans