T20: Mixed types from T01-T20
50. Pharmacokinetics 50.1) PK Basic parameters 50.1.3) Area Under Curve (AUC)
50.1.3.1) AUC basic concepts Normal 1
Total tried: Correct: Wrong:
How much drug has to be administered to a patient weighing 73 Kg so that the plasma concentration is 4.75 mg/L? Given that, the Volume of distribution of the drug is 0.68 L/Kg.
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lb equals 235.79 mg kg
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Total volume of distribution (V) for this patient will be:
`0.68 \quad L/(Kg) × 73 \quad Kg = 49.64 \quad L`
Concentration (`C_{0}`) = `4.75 \quad (mg)/L`;
Drug quantity (`X_{0}`) =?
We know that,
`C_{0}=X_{0}/V`
`therefore X_{0} = C_{0} × V`
`= 4.75 \quad (mg)/L × 49.64 \quad L = 235.79 \quad mg`. Ans.