T20: Mixed types from T01-T20

50. Pharmacokinetics 50.1) PK Basic parameters 50.1.3) Area Under Curve (AUC)

50.1.3.1) AUC basic concepts Normal 1


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How much drug has to be administered to a patient weighing 73 Kg so that the plasma concentration is 4.75 mg/L? Given that, the Volume of distribution of the drug is 0.68 L/Kg.


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lb equals 235.79 mg kg

    Total volume of distribution (V) for this patient will be:
    `0.68 \quad L/(Kg) × 73 \quad Kg = 49.64 \quad L`
    Concentration (`C_{0}`) = `4.75 \quad (mg)/L`;
    Drug quantity (`X_{0}`) =?
    We know that,
    `C_{0}=X_{0}/V`
    `therefore X_{0} = C_{0} × V`
    `= 4.75 \quad (mg)/L × 49.64 \quad L = 235.79 \quad mg`. Ans.


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