Alcohol proof general calculation
1. Units and Conversion 1.4) Alcohol proof 1.4.1) Alcohol proof
1.4.1.1) Alcohol proof Normal 1
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Express 6 gallons of 40 v/v alcohol in terms of the number of proof gallons.
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lb equals 4.8 g kg
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Alcohol proof is defined as twice the volume percentage of ethanol (measured at 60 °F)
Example 1: At 80 proof (40% alcohol) would be 0.8 proof gallons per gallon of liquid.
Example 2: At 125 proof (87.5% alcohol), a gallon of liquid would be 1.25 proof gallons
Thus, 40 % v/v percent will be 2 × 40 = 80 proof, which is 0.8 proof gallons per gallon of liquid.
This is a volume expansion or concentration dilution type problem. The essential formula is `Q_1C_1 = Q_2C_2`.
Here,
`Q_1` = initial quantity = `6\quadGal`.
`C_1` = initial concentration = `40 %`v/v
`Q_2` = final quantity = `?\quad Gal`.
`C_2` = final concentration = `50%`v/v
Therefore, rearranging the formula, we get:
`Q_2 = (Q_1×C_1)/(C_2)` `therefore Q_2 = (6 × 40) /50=4.8` proof gallons, Ans.