Determine molarity from weight of drug and volume of the solution

4. Moles and Molarity 4.2) Molarity 4.2.1) Molarity - general Molarity - general Normal 1

Total tried:       Correct:       Wrong:

81.7 g of calcium gluconate is dissolved in 950 mL of solution. If the molecular weight of calcium gluconate is 430, then determine the molarity (M) of the solution

Click on the button below to see the answer and explanations

Notice: Undefined variable: input_value1 in /home/jshzub/web/ on line 220
lb equals 0.2 M kg

    Molarity is the number of moles (`n`) dissolved per liter of solution (`V`). Again, mole is the weight in gram (`g`) divided by the molecular weight (`a`).
    In this example, the volume of the solution is 950 mL, or 0.95 L.

    [1] Using formula method:
    `M=g/(aV)=(81.7\quad g)/(430\quad (g/(mol)) × 0.95\quad L)`
    `therefore M = 0.2 (mol)/L=0.2` without unit, Ans.

    [2] Using conceptual method:
    First, count the number of moles (`n`) of calcium gluconate present in this solution:
    `=(weight\quad i n \quad g)/(mol ecu lar\quad wt)=(81.7\quad g)/(430 \quad (g/(mol)))=0.19 \quad mol`
    Then, calculate how many moles will be present in 1L of solution. Using equation, we can write:
    `(0.19\quad mol e)/(950 \quad mL)=x/(1000 \quad mL) therefore x = 0.2` Ans.

Notice: Undefined index: TOTALTRY in /home/jshzub/web/ on line 675