(type 3) Calculate mg per volume from mEq per volume
5. mEq and mOsmol 5.1) mEq 5.1.1) mEq - General
5.1.1.1) mEq from weight/volume Normal 1
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If potassium citrate monohydrated solution is expressed as 0.0417 mEq/mL, then how many milligram of potassium citrate monohydrated will be present in each 10 mL of the solution? Round to the nearest tenth. The molecular weight of potassium citrate monohydrated is 324 g/mol.
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lb equals 45 mg/10mL kg
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The molecular weight of potassium citrate monohydrated = 324.
Valence or charge = 3.
Therefore, we can write: 324 mg = 3 mEq.
Since the question needs mg/10 mL as the final unit, we keep 324 mg in the starting numerator. So, 3 mEq will be the denominator.
Also, the solution contains 0.0417 mEq per mL; therefore, the mEq is used as the numerator for the second fraction, in order to cancel out. The dimensional analysis will be like this:
`(324 \quad mg)/(3 \quad mEq) × (0.0417 \quad mEq)/(1 \quad mL) × (10 \quad mL)/(10 \quad mL) = 45\quad (mg)/(10 \quad mL)` Ans.