T11: Mixed problems from T1 - T11.

50. Pharmacokinetics 50.1) PK Basic parameters 50.1.2) Clearance Clearance basic concepts Normal 1

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If a patient weighing 145 Kg is given 310.0825 mg of drug as an IV bolus, then determine the concentration of the drug in the blood. For this drug, the volume of distribution is 0.91 L/Kg.

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lb equals 2.35 mg kg

    Total volume of distribution (V) for this patient will be:
    `0.91 \quad L/(Kg) × 145 \quad Kg = 131.95 \quad L`
    Drug quantity (`X_{0}`) =310.0825 mg
    Concentration (`C_{0}`) = ?
    We know that,
    `therefore C_{0} = (310.0825 \quad mg)/ (131.95 \quad L) = 2.35 \quad (mg)/L`. Ans.