T11: Mixed problems from T1 - T11.

50. Pharmacokinetics 50.1) PK Basic parameters 50.1.2) Clearance Clearance basic concepts Normal 1

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If a patient weighing 187 Kg is given 483.395 mg of drug as an IV bolus, then determine the concentration of the drug in the blood. For this drug, the volume of distribution is 0.55 L/Kg.

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lb equals 4.7 mg kg

    Total volume of distribution (V) for this patient will be:
    `0.55 \quad L/(Kg) × 187 \quad Kg = 102.85 \quad L`
    Drug quantity (`X_{0}`) =483.395 mg
    Concentration (`C_{0}`) = ?
    We know that,
    `therefore C_{0} = (483.395 \quad mg)/ (102.85 \quad L) = 4.7 \quad (mg)/L`. Ans.