T11: Mixed problems from T1 - T11.

50. Pharmacokinetics 50.1) PK Basic parameters 50.1.2) Clearance Clearance basic concepts Normal 1

Total tried:       Correct:       Wrong:

The plasma half life `t_{1/2}` of a drug is 3.48 h. If its volume of distribution in a patient is 43.92 L, then determine the clearance of the drug.

Click on the button below to see the answer and explanations

Notice: Undefined variable: input_value1 in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 220
lb equals 8.74 L/h kg

    We know that, clearance (Cl) is the product of elimination rate constant (K) and volume of distribution (V).

    ` Cl = K × V `.

    Also, the relationship between K and plasma half life, `t_{½}` is:
    `t_{½}=0.693/K ⇒ K=0.693/(3.48 \quad h)=0.199 \quad h^{-1}`

    Plugging the values given in this question we get:
    ` Cl = 0.199 \quad h^{-1} × 43.92 \quad L = 8.74 \quad L/h ` Ans

Notice: Undefined index: TOTALTRY in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 675