T02) Concentration from volume and dose

50. Pharmacokinetics 50.1) PK Basic parameters 50.1.1) Dose, Volume and Concentration

50.1.1.1) Basic parameters Easy 1


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If a patient weighing 181 Kg is given 98.7536 mg of drug as an IV bolus, then determine the concentration of the drug in the blood. For this drug, the volume of distribution is 0.88 L/Kg.


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lb equals 0.62 mg kg

    Total volume of distribution (V) for this patient will be:
    `0.88 \quad L/(Kg) × 181 \quad Kg = 159.28 \quad L`
    Drug quantity (`X_{0}`) =98.7536 mg
    Concentration (`C_{0}`) = ?
    We know that,
    `C_{0}=X_{0}/V`
    `therefore C_{0} = (98.7536 \quad mg)/ (159.28 \quad L) = 0.62 \quad (mg)/L`. Ans.


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