(type 5) mEq problems - randomized
5. mEq and mOsmol 5.1) mEq 5.1.1) mEq - General
5.1.1.1) mEq from weight/volume Normal 1
Total tried: Correct: Wrong:
5. mEq and mOsmol 5.1) mEq 5.1.1) mEq - General
5.1.1.1) mEq from weight/volume Normal 1
Total tried: Correct: Wrong:
If potassium acetate solution is expressed as 15.31 mEq/L, then how many milligram of potassium acetate will be present in each 1 mL of the solution? Round your answer to the nearest tenth. The molecular weight of potassium acetate is 98 g/mol.
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lb equals 1.5 mg/1mL kg