Dilution Problem - Mixed category

9. Altering Product Strength 9.1) Dilution 9.1.1) Dilution

9.1.1.1) Find initial concentration in dilution Challenging 1


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What concentration of a 12 mL solution do you need to make 239.5 mL of a 1.08% solution?


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lb equals 21.5 % kg

    This is a volume expansion or concentration dilution type problem. The essential formula is `Q_1C_1 = Q_2C_2`.
    Here,

    `Q_1` = initial quantity = `12\quadmL`.
    `C_1` = initial concentration = `?\quad%`
    `Q_2` = final quantity = `239.5\quad mL`.
    `C_2` = final concentration = `1.08\quad %`

    Therefore, rearranging the formula, we get:
    `C_1 = (Q_2 × C_2)/(Q_1)`

    `therefore C_1 = (239.5 × 1.08) /12=21.5\quad%` (Ans.).