Dilution Problem - Find quantity of solvent
9. Altering Product Strength 9.1) Dilution 9.1.1) Dilution
9.1.1.1) Find initial concentration in dilution Easy 1
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Calculate the quantity of solvent you need to add into 32.5 mL of a 35.5 % solution to prepare a 5.78 % solution?
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lb equals 167 mL kg
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This is a volume expansion or concentration dilution type problem. The essential formula is `Q_1C_1 = Q_2C_2`.
Here,
`Q_1` = initial quantity = `32.5\quadmL`.
`C_1` = initial concentration = `35.5\quad%`
`Q_2` = final quantity = `?\quad mL`.
`C_2` = final concentration = `5.78\quad %`
Therefore, rearranging the formula, we get:
`Q_2 = (Q_1 × C_1)/(C_2)` `therefore Q_2 = (32.5 × 35.5) /5.78=199.5\quad mL` in nearest whole number.
Now, subtract the initial quantity of the solution (`32.5\quadmL`) from this final quantity (`199.5\quadmL`) to determine the amount of solvent to be added: `199.5\quadmL-32.5\quadmL=167\quadmL`. (Ans)