Dilution Problem - Find quantity of solvent

9. Altering Product Strength 9.1) Dilution 9.1.1) Dilution

9.1.1.1) Find initial concentration in dilution Easy 1


Total tried:       Correct:       Wrong:

Calculate the quantity of solvent you need to add into 31.5 mL of a 34.75 % solution to prepare a 7.6 % solution?


Click on the button below to see the answer and explanations


Notice: Undefined variable: input_value1 in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 220
lb equals 112.5 mL kg

    This is a volume expansion or concentration dilution type problem. The essential formula is `Q_1C_1 = Q_2C_2`.
    Here,

    `Q_1` = initial quantity = `31.5\quadmL`.
    `C_1` = initial concentration = `34.75\quad%`
    `Q_2` = final quantity = `?\quad mL`.
    `C_2` = final concentration = `7.6\quad %`

    Therefore, rearranging the formula, we get:
    `Q_2 = (Q_1 × C_1)/(C_2)` `therefore Q_2 = (31.5 × 34.75) /7.6=144\quad mL` in nearest whole number.

    Now, subtract the initial quantity of the solution (`31.5\quadmL`) from this final quantity (`144\quadmL`) to determine the amount of solvent to be added: `144\quadmL-31.5\quadmL=112.5\quadmL`. (Ans)


Notice: Undefined index: TOTALTRY in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 675