### T03) Find C0 from Ct, k and t

50. Pharmacokinetics 50.2) Plasma concentrations over time 50.2.1) Plasma concentrations over time

T01: Later plasma concentration Normal 1

Total tried:       Correct:       Wrong:

A 93 -kg patient has received an IV bolus injection of a drug. A sample of blood was collected 10 hours after the first collection. The drug follows a first order elimination process, and its elimination rate constant is 0.212 \quad h^{-1}. If the plasma concentration was 0.317 mg/L in the second sample, then what was the concentration in the initial sample? Click on the button below to see the answer and explanations

Notice: Undefined variable: input_value1 in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 220
lb equals 2.64 mg/L kg

For a first order process,
C_{t}=C_{0}×e^(-kt)
It may be re-organized as:
C_{0}=C_{t}/(e^(-kt))
Or, C_{0}=C_{t}×e^(kt)
Plugging the values in above equation, we get:
C_{0}=0.317 × e^(0.212 × 10)
∴ C_{0}=2.64
Thus, the initial concentration was: 2.64 mg/L. (Ans).

#### 123 ,Lorem Ipsum dummy Text E-mail: [email protected]

Notice: Undefined index: TOTALTRY in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 675