Dilution Problem - Find Final Concentration

9. Altering Product Strength 9.1) Dilution 9.1.1) Dilution

9.1.1.1) Find initial concentration in dilution Easy 1


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32 mL of a 40 % solution is diluted to make the final volume of 225 mL. Calculate the new concentration.


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lb equals 5.69 % kg

    This is a volume expansion or concentration dilution type problem. The essential formula is `Q_1C_1 = Q_2C_2`.
    Here,

    `Q_1` = initial quantity = `32\quadmL`.
    `C_1` = initial concentration = `40\quad%`
    `Q_2` = final quantity = `225\quad mL`.
    `C_2` = final concentration = `?\quad %`

    Therefore, rearranging the formula, we get:
    `C_2 = (Q_1 × C_1)/(Q_2)`

    `therefore C_2 = (32 × 40) /225=5.69\quad %` (Ans.).