Type 1: Determine mOsmol from weight or percent of the solute

5. mEq and mOsmol 5.2) mOsmol 5.2.1) mOsmol - General

5.2.1.1) mOsmol - General Normal 1


Total tried:       Correct:       Wrong:

Express the concentration of 1.3 % (w/v) potassium acetate solution as mOsmol per liter. The molecular weight of potassium acetate is 98 g/mol


Click on the button below to see the answer and explanations

lb equals 265.31 mOsmol/L kg

    For potassium acetate , the 'golden formula' is:
    1 mmol = `[98]` mg = `[1]` mEq = `[2]` mOsmol.

    Osmolarity is the number of mOsmol in 1000 mL (1 L) of the solution.
    Using dimensional analysis:
    `(1300 \quad mg)/(100 \quad mL) × (2 \quad mOsmol)/(98 \quad mg) × (1000 \quad mL)/(1 \quad L) = 265.31 \quad (mOsmol)/(1 \quad L)`.
    Therefore, the osmolarity is 265.31. Ans.