Type 1: Determine mOsmol from weight or percent of the solute

5. mEq and mOsmol 5.2) mOsmol 5.2.1) mOsmol - General mOsmol - General Normal 1

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A solution contains 97.5 mg of calcium chloride dihydrate in each 15 mL (the MW of calcium chloride dihydrate is 147). Calculate the osmolarity of this solution

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lb equals 132.65 mOsmol/L kg

    For calcium chloride dihydrate , the 'golden formula' is:
    1 mmol = `[147]` mg = `[2]` mEq = `[3]` mOsmol.

    Osmolarity is the number of mOsmol in 1000 mL (1 L) of the solution.
    Using dimensional analysis:
    `(97.5 \quad mg)/(15 \quad mL) × (1.9898 \quad mOsmol)/(147 \quad mg) × (1000 \quad mL)/(1 \quad L) = 132.65 \quad (mOsmol)/(1 \quad L)`.
    Therefore, the osmolarity is 132.65. Ans.

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