### Type 1: Determine mOsmol from weight or percent of the solute

5. mEq and mOsmol 5.2) mOsmol 5.2.1) mOsmol - General

5.2.1.1) mOsmol - General Normal 1

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A solution contains 97.5 mg of calcium chloride dihydrate in each 15 mL (the MW of calcium chloride dihydrate is 147). Calculate the osmolarity of this solution Click on the button below to see the answer and explanations

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lb equals 132.65 mOsmol/L kg

For calcium chloride dihydrate , the 'golden formula' is:
1 mmol =  mg =  mEq =  mOsmol.

Osmolarity is the number of mOsmol in 1000 mL (1 L) of the solution.
Using dimensional analysis:
(97.5 \quad mg)/(15 \quad mL) × (1.9898 \quad mOsmol)/(147 \quad mg) × (1000 \quad mL)/(1 \quad L) = 132.65 \quad (mOsmol)/(1 \quad L).
Therefore, the osmolarity is 132.65. Ans.

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