Type 1: Determine mOsmol from weight or percent of the solute
5. mEq and mOsmol 5.2) mOsmol 5.2.1) mOsmol - General
5.2.1.1) mOsmol - General Normal 1
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Express the concentration of 0.8 % (w/v) potassium acetate solution as mOsmol per liter. The molecular weight of potassium acetate is 98 g/mol
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lb equals 163.27 mOsmol/L kg
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For potassium acetate , the 'golden formula' is:
1 mmol = `[98]` mg = `[1]` mEq = `[2]` mOsmol.
Osmolarity is the number of mOsmol in 1000 mL (1 L) of the solution.
Using dimensional analysis:
`(800 \quad mg)/(100 \quad mL) × (2 \quad mOsmol)/(98 \quad mg) × (1000 \quad mL)/(1 \quad L) = 163.27 \quad (mOsmol)/(1 \quad L)`.
Therefore, the osmolarity is 163.27. Ans.