### T04) Find C0 from Ct, t half and t

50. Pharmacokinetics 50.2) Plasma concentrations over time 50.2.1) Plasma concentrations over time

T01: Later plasma concentration Normal 1

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A 190 -kg patient has received an IV bolus injection of a drug. A sample of blood was collected 4.8 hours after the first collection. The drug follows a first order elimination process, and its plasma half life is 8.45 hours. If the plasma concentration was 2.806 mg/L in the second sample, then what was the concentration in the initial sample? Click on the button below to see the answer and explanations

lb equals 4.16 mg/L kg

For a first order process,
C_{t}=C_{0}×e^(-kt)
It may be re-organized as:
C_{0}=C_{t}/(e^(-kt))
Or, C_{0}=C_{t}×e^(kt) ..... (1)
In the question, k is not provided, but we can derive it from the equation below:
k=0.693/t_{½}=0.693/(8.45 \quad h)=0.082 \quad h^{-1}.
Plugging the values in equation (1), we get:
C_{0}=2.806 × e^(0.082 × 4.8)
∴ C_{0}=4.16
Thus, the initial concentration was: 4.16 mg/L. (Ans).