SG - volume of stock as the source of drug

2. Density & Specific Gravity 2.1) Specific Gravity 2.1.3) SG - volume of stock as the source of drug

2.1.3.1) SG - volume of stock as the source of drug Hard 1


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A pharmacist needs 4.68 g of a drug. The drug is available as a solution form in which every 100 g contains only 63 g of the pure drug. If the solution has a specific gravity of 0.72, then determine the volume of the solution that you need to compound the product.


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lb equals 10.32 mL kg

    The quantity of pure drug = 4.68 g.

    Step 1: determine the weight of the solution which will be used as the source of the drug.
    100 g of the solution provides 63 g of the drug.
    Therefore,

    `(100\quad g\quad solution)/(63\quad g\quad drug)=x/(4.68\quad g\quad drug)`
    Or, `x = 7.429\quad g\quad`  solution.

    Step 2: determine the volume of the solution from its specific gravity (0.72) and weight in grams (7.429).
    We know that,
    `SG = (Weight\quad i n\quad grams)/(volume\quad i n\quad mL)`
    Or, `Volume\quad i n \quad mL = (Weight\quad i n \quad grams) / (SG)`
    Or `Volume\quad i n \quad mL = 7.429/0.72 = 10.317`.
    Answer.