SG - volume of stock as the source of drug
2. Density & Specific Gravity 2.1) Specific Gravity 2.1.3) SG - volume of stock as the source of drug
2.1.3.1) SG - volume of stock as the source of drug Hard 1
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A pharmacist needs 1.19 g of a drug. The drug is available as a solution form in which every 100 g contains only 86 g of the pure drug. If the solution has a specific gravity of 1.06, then determine the volume of the solution that you need to compound the product.
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lb equals 1.31 mL kg
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The quantity of pure drug = 1.19 g.
Step 1: determine the weight of the solution which will be used as the source of the drug.
100 g of the solution provides 86 g of the drug.
Therefore,
`(100\quad g\quad solution)/(86\quad g\quad drug)=x/(1.19\quad g\quad drug)`
Or, `x = 1.384\quad g\quad` solution.
Step 2: determine the volume of the solution from its specific gravity (1.06) and weight in grams (1.384).
We know that,
`SG = (Weight\quad i n\quad grams)/(volume\quad i n\quad mL)`
Or, `Volume\quad i n \quad mL = (Weight\quad i n \quad grams) / (SG)`
Or `Volume\quad i n \quad mL = 1.384/1.06 = 1.305`.
Answer.