### SG - volume of stock as the source of drug

2. Density & Specific Gravity 2.1) Specific Gravity 2.1.3) SG - volume of stock as the source of drug

2.1.3.1) SG - volume of stock as the source of drug Hard 1

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A pharmacist needs 4.68 g of a drug. The drug is available as a solution form in which every 100 g contains only 63 g of the pure drug. If the solution has a specific gravity of 0.72, then determine the volume of the solution that you need to compound the product. Click on the button below to see the answer and explanations

lb equals 10.32 mL kg

The quantity of pure drug = 4.68 g.

Step 1: determine the weight of the solution which will be used as the source of the drug.
100 g of the solution provides 63 g of the drug.
Therefore,

(100\quad g\quad solution)/(63\quad g\quad drug)=x/(4.68\quad g\quad drug)
Or, x = 7.429\quad g\quad  solution.

Step 2: determine the volume of the solution from its specific gravity (0.72) and weight in grams (7.429).
We know that,
SG = (Weight\quad i n\quad grams)/(volume\quad i n\quad mL)
Or, Volume\quad i n \quad mL = (Weight\quad i n \quad grams) / (SG)
Or Volume\quad i n \quad mL = 7.429/0.72 = 10.317.