SG - volume of stock as the source of drug
2. Density & Specific Gravity 2.1) Specific Gravity 2.1.3) SG - volume of stock as the source of drug
2.1.3.1) SG - volume of stock as the source of drug Hard 1
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A pharmacist needs 13.4 g of a drug. The drug is available as a solution form in which every 100 g contains only 69 g of the pure drug. If the solution has a specific gravity of 0.93, then determine the volume of the solution that you need to compound the product.
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lb equals 20.88 mL kg
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The quantity of pure drug = 13.4 g.
Step 1: determine the weight of the solution which will be used as the source of the drug.
100 g of the solution provides 69 g of the drug.
Therefore,
`(100\quad g\quad solution)/(69\quad g\quad drug)=x/(13.4\quad g\quad drug)`
Or, `x = 19.42\quad g\quad` solution.
Step 2: determine the volume of the solution from its specific gravity (0.93) and weight in grams (19.42).
We know that,
`SG = (Weight\quad i n\quad grams)/(volume\quad i n\quad mL)`
Or, `Volume\quad i n \quad mL = (Weight\quad i n \quad grams) / (SG)`
Or `Volume\quad i n \quad mL = 19.42/0.93 = 20.882`.
Answer.